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131244412031 is a prime number
BaseRepresentation
bin111101000111011000…
…1101100110001111111
3110112202122111221000022
41322032301230301333
54122242032141111
6140143131122355
712324234044525
oct1721661546177
9415678457008
10131244412031
115072a05a327
12215295a33bb
13c4b7948b05
1464d087a315
1536322232db
hex1e8ec6cc7f

131244412031 has 2 divisors, whose sum is σ = 131244412032. Its totient is φ = 131244412030.

The previous prime is 131244412003. The next prime is 131244412043. The reversal of 131244412031 is 130214442131.

It is a strong prime.

It is an emirp because it is prime and its reverse (130214442131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131244412031 - 214 = 131244395647 is a prime.

It is a super-2 number, since 2×1312444120312 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131244412001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622206015 + 65622206016.

It is an arithmetic number, because the mean of its divisors is an integer number (65622206016).

Almost surely, 2131244412031 is an apocalyptic number.

131244412031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131244412031 is an equidigital number, since it uses as much as digits as its factorization.

131244412031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 131244412031 its reverse (130214442131), we get a palindrome (261458854162).

The spelling of 131244412031 in words is "one hundred thirty-one billion, two hundred forty-four million, four hundred twelve thousand, thirty-one".