Base | Representation |
---|---|
bin | 1011111011111100011000… |
… | …1011111111101100011000 |
3 | 1201110200111111100210020112 |
4 | 2332333012023333230120 |
5 | 3210012333212410040 |
6 | 43525142242343452 |
7 | 2523132052240052 |
oct | 276770613775430 |
9 | 51420444323215 |
10 | 13124450122520 |
11 | 4200058a38820 |
12 | 157b73395ab88 |
13 | 742826b04879 |
14 | 3353263b28d2 |
15 | 17b5e5177365 |
hex | befc62ffb18 |
13124450122520 has 64 divisors (see below), whose sum is σ = 32515630156800. Its totient is φ = 4727924241280.
The previous prime is 13124450122519. The next prime is 13124450122541. The reversal of 13124450122520 is 2522105442131.
It is a super-2 number, since 2×131244501225202 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139337480 + ... + 139431639.
It is an arithmetic number, because the mean of its divisors is an integer number (508056721200).
Almost surely, 213124450122520 is an apocalyptic number.
13124450122520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13124450122520 is an abundant number, since it is smaller than the sum of its proper divisors (19391180034280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13124450122520 is a wasteful number, since it uses less digits than its factorization.
13124450122520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 278769248 (or 278769244 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 13124450122520 its reverse (2522105442131), we get a palindrome (15646555564651).
The spelling of 13124450122520 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fifty million, one hundred twenty-two thousand, five hundred twenty".
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