Base | Representation |
---|---|
bin | 10011000110010100100… |
… | …000010110010010010100 |
3 | 11122110200100111220022102 |
4 | 103012110200112102110 |
5 | 133000402333030030 |
6 | 2442533442221232 |
7 | 163551616314464 |
oct | 23062440262224 |
9 | 4573610456272 |
10 | 1312456533140 |
11 | 466678551985 |
12 | 192443054818 |
13 | 969c1a054cc |
14 | 47747a85ba4 |
15 | 242177c4c45 |
hex | 13194816494 |
1312456533140 has 24 divisors (see below), whose sum is σ = 2783447424072. Its totient is φ = 519784764800.
The previous prime is 1312456533107. The next prime is 1312456533163. The reversal of 1312456533140 is 413356542131.
It can be written as a sum of positive squares in 4 ways, for example, as 494484614416 + 817971918724 = 703196^2 + 904418^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1312456533094 and 1312456533103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 324863459 + ... + 324867498.
It is an arithmetic number, because the mean of its divisors is an integer number (115976976003).
Almost surely, 21312456533140 is an apocalyptic number.
1312456533140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1312456533140 is an abundant number, since it is smaller than the sum of its proper divisors (1470990890932).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312456533140 is a wasteful number, since it uses less digits than its factorization.
1312456533140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 649731067 (or 649731065 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 1312456533140 in words is "one trillion, three hundred twelve billion, four hundred fifty-six million, five hundred thirty-three thousand, one hundred forty".
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