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1312513251317 is a prime number
BaseRepresentation
bin10011000110010111111…
…000101101011111110101
311122110211022020111000122
4103012113320231133311
5133001011343020232
62442543230021325
7163553205362552
oct23062770553765
94573738214018
101312513251317
114666a7571104
1219245a047845
1396a006a3768
144775140ba29
152421c77a312
hex13197e2d7f5

1312513251317 has 2 divisors, whose sum is σ = 1312513251318. Its totient is φ = 1312513251316.

The previous prime is 1312513251199. The next prime is 1312513251319. The reversal of 1312513251317 is 7131523152131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 665519850436 + 646993400881 = 815794^2 + 804359^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312513251317 - 214 = 1312513234933 is a prime.

Together with 1312513251319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312513251319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656256625658 + 656256625659.

It is an arithmetic number, because the mean of its divisors is an integer number (656256625659).

Almost surely, 21312513251317 is an apocalyptic number.

It is an amenable number.

1312513251317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312513251317 is an equidigital number, since it uses as much as digits as its factorization.

1312513251317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18900, while the sum is 35.

The spelling of 1312513251317 in words is "one trillion, three hundred twelve billion, five hundred thirteen million, two hundred fifty-one thousand, three hundred seventeen".