Base | Representation |
---|---|
bin | 11101110101111110010111… |
… | …111101011000110010100000 |
3 | 122012201121112021011001101201 |
4 | 131311332113331120302200 |
5 | 114200420011443103100 |
6 | 1143052313452210544 |
7 | 36434451123034555 |
oct | 3565762775306240 |
9 | 565647467131351 |
10 | 131252455050400 |
11 | 3890394314a042 |
12 | 12879731769a54 |
13 | 5831090431648 |
14 | 245a91d0c6a2c |
15 | 102929e42636a |
hex | 775f97f58ca0 |
131252455050400 has 144 divisors (see below), whose sum is σ = 321699611657088. Its totient is φ = 52291443456000.
The previous prime is 131252455050389. The next prime is 131252455050461. The reversal of 131252455050400 is 4050554252131.
It is a super-3 number, since 3×1312524550504003 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131252455050400.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 730743004 + ... + 730922596.
It is an arithmetic number, because the mean of its divisors is an integer number (2234025080952).
Almost surely, 2131252455050400 is an apocalyptic number.
131252455050400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131252455050400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (160849805828544).
131252455050400 is an abundant number, since it is smaller than the sum of its proper divisors (190447156606688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131252455050400 is a wasteful number, since it uses less digits than its factorization.
131252455050400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183255 (or 183242 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 37.
The spelling of 131252455050400 in words is "one hundred thirty-one trillion, two hundred fifty-two billion, four hundred fifty-five million, fifty thousand, four hundred".
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