13125403021453 has 2 divisors, whose sum is σ = 13125403021454. Its totient is φ = 13125403021452.

The previous prime is 13125403021421. The next prime is 13125403021487. The reversal of 13125403021453 is 35412030452131.

It is an a-pointer prime, because the next prime (13125403021487) can be obtained adding 13125403021453 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9006703247689 + 4118699773764 = 3001117^2 + 2029458^2 .

It is an emirp because it is prime and its reverse (35412030452131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13125403021453 - 2⁵ = 13125403021421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13125403021153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562701510726 + 6562701510727.

It is an arithmetic number, because the mean of its divisors is an integer number (6562701510727).

Almost surely, 2^{13125403021453} is an apocalyptic number.

It is an amenable number.

13125403021453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125403021453 is an equidigital number, since it uses as much as digits as its factorization.

13125403021453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 13125403021453 its reverse (35412030452131), we get a palindrome (48537433473584).

The spelling of 13125403021453 in words is "thirteen trillion, one hundred twenty-five billion, four hundred three million, twenty-one thousand, four hundred fifty-three".