Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …001100000111111010101 |
3 | 11122112002020010221201221 |
4 | 103012310321200333111 |
5 | 133003011000021433 |
6 | 2443103414450341 |
7 | 163601235603355 |
oct | 23066471407725 |
9 | 4575066127657 |
10 | 1313000001493 |
11 | 4669272a8784 |
12 | 1925750639b1 |
13 | 96a7a499a0b |
14 | 47799d14b65 |
15 | 2424a37772d |
hex | 131b4e60fd5 |
1313000001493 has 2 divisors, whose sum is σ = 1313000001494. Its totient is φ = 1313000001492.
The previous prime is 1313000001463. The next prime is 1313000001497. The reversal of 1313000001493 is 3941000003131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 747605788164 + 565394213329 = 864642^2 + 751927^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313000001493 - 217 = 1312999870421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313000001497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500000746 + 656500000747.
It is an arithmetic number, because the mean of its divisors is an integer number (656500000747).
Almost surely, 21313000001493 is an apocalyptic number.
It is an amenable number.
1313000001493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313000001493 is an equidigital number, since it uses as much as digits as its factorization.
1313000001493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 1313000001493 in words is "one trillion, three hundred thirteen billion, one thousand, four hundred ninety-three".
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