131301130112130 has 32 divisors (see below), whose sum is σ = 343770231567168. Its totient is φ = 31830576996800.

The previous prime is 131301130112083. The next prime is 131301130112137. The reversal of 131301130112130 is 31211031103131.

It is a junction number, because it is equal to n+sod(n) for n = 131301130112097 and 131301130112106.

It is not an unprimeable number, because it can be changed into a prime (131301130112137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 198941105901 + ... + 198941106560.

It is an arithmetic number, because the mean of its divisors is an integer number (10742819736474).

Almost surely, 2^{131301130112130} is an apocalyptic number.

131301130112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131301130112130 is an abundant number, since it is smaller than the sum of its proper divisors (212469101455038).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131301130112130 is a wasteful number, since it uses less digits than its factorization.

131301130112130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 397882212482.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 131301130112130 its reverse (31211031103131), we get a palindrome (162512161215261).

The spelling of 131301130112130 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty million, one hundred twelve thousand, one hundred thirty".