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1313012421404 = 221933751265517
BaseRepresentation
bin10011000110110101101…
…000111001001100011100
311122112010002111221122122
4103012311220321030130
5133003022134441104
62443104541002112
7163601446302125
oct23066550711434
94575102457578
101313012421404
11466933310a72
12192579253338
1396a7cc27b88
144779b82904c
152424b4cc6be
hex131b5a3931c

1313012421404 has 24 divisors (see below), whose sum is σ = 2425884311760. Its totient is φ = 620107681536.

The previous prime is 1313012421337. The next prime is 1313012421407. The reversal of 1313012421404 is 4041242103131.

It is a super-2 number, since 2×13130124214042 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313012421407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25607147 + ... + 25658370.

It is an arithmetic number, because the mean of its divisors is an integer number (101078512990).

Almost surely, 21313012421404 is an apocalyptic number.

It is an amenable number.

1313012421404 is a deficient number, since it is larger than the sum of its proper divisors (1112871890356).

1313012421404 is a wasteful number, since it uses less digits than its factorization.

1313012421404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51265877 (or 51265875 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1313012421404 its reverse (4041242103131), we get a palindrome (5354254524535).

The spelling of 1313012421404 in words is "one trillion, three hundred thirteen billion, twelve million, four hundred twenty-one thousand, four hundred four".

Divisors: 1 2 4 19 38 76 337 674 1348 6403 12806 25612 51265517 102531034 205062068 974044823 1948089646 3896179292 17276479229 34552958458 69105916916 328253105351 656506210702 1313012421404