131301433120 has 96 divisors (see below), whose sum is σ = 364430404800. Its totient is φ = 44073200640.

The previous prime is 131301433099. The next prime is 131301433127. The reversal of 131301433120 is 21334103131.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 131301433091 and 131301433100.

It is not an unprimeable number, because it can be changed into a prime (131301433127) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2846470 + ... + 2892229.

It is an arithmetic number, because the mean of its divisors is an integer number (3796150050).

Almost surely, 2^131301433120 is an apocalyptic number.

131301433120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131301433120 is an abundant number, since it is smaller than the sum of its proper divisors (233128971680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131301433120 is a wasteful number, since it uses less digits than its factorization.

131301433120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5738738 (or 5738730 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 131301433120 its reverse (21334103131), we get a palindrome (152635536251).

The spelling of 131301433120 in words is "one hundred thirty-one billion, three hundred one million, four hundred thirty-three thousand, one hundred twenty".