Base | Representation |
---|---|
bin | 1011111100010001111011… |
… | …1100001010100100101100 |
3 | 1201111020102120221220121020 |
4 | 2333010132330022210230 |
5 | 3210111204413043200 |
6 | 43531540221334140 |
7 | 2523425304320034 |
oct | 277043674124454 |
9 | 51436376856536 |
10 | 13130234112300 |
11 | 4202556940968 |
12 | 1580888a07350 |
13 | 7432391cbc26 |
14 | 3357146328c4 |
15 | 17b832d41ea0 |
hex | bf11ef0a92c |
13130234112300 has 72 divisors (see below), whose sum is σ = 38186984324496. Its totient is φ = 3483253800960.
The previous prime is 13130234112217. The next prime is 13130234112319. The reversal of 13130234112300 is 321143203131.
It is a super-2 number, since 2×131302341123002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 113329269 + ... + 113445068.
Almost surely, 213130234112300 is an apocalyptic number.
13130234112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13130234112300 is an abundant number, since it is smaller than the sum of its proper divisors (25056750212196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130234112300 is a wasteful number, since it uses less digits than its factorization.
13130234112300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226774547 (or 226774540 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13130234112300 its reverse (321143203131), we get a palindrome (13451377315431).
The spelling of 13130234112300 in words is "thirteen trillion, one hundred thirty billion, two hundred thirty-four million, one hundred twelve thousand, three hundred".
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