Base | Representation |
---|---|
bin | 1011111100010100110101… |
… | …1000111100111001100000 |
3 | 1201111022102220100100121211 |
4 | 2333011031120330321200 |
5 | 3210114303413113100 |
6 | 43532145420355504 |
7 | 2523453516252124 |
oct | 277051530747140 |
9 | 51438386310554 |
10 | 13131013410400 |
11 | 4202916822086 |
12 | 1580a659a5b94 |
13 | 7433317b4072 |
14 | 335789d2d584 |
15 | 17b87b47a1ba |
hex | bf14d63ce60 |
13131013410400 has 72 divisors (see below), whose sum is σ = 32062626141840. Its totient is φ = 5251333839360.
The previous prime is 13131013410377. The next prime is 13131013410457. The reversal of 13131013410400 is 401431013131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2255397 + ... + 5599003.
It is an arithmetic number, because the mean of its divisors is an integer number (445314251970).
Almost surely, 213131013410400 is an apocalyptic number.
13131013410400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13131013410400 is an abundant number, since it is smaller than the sum of its proper divisors (18931612731440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131013410400 is a wasteful number, since it uses less digits than its factorization.
13131013410400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3348536 (or 3348523 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13131013410400 its reverse (401431013131), we get a palindrome (13532444423531).
The spelling of 13131013410400 in words is "thirteen trillion, one hundred thirty-one billion, thirteen million, four hundred ten thousand, four hundred".
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