13131112304112 has 80 divisors (see below), whose sum is σ = 37372256772480. Its totient is φ = 3939727648000.

The previous prime is 13131112304071. The next prime is 13131112304147. The reversal of 13131112304112 is 21140321113131.

It is a super-3 number, since 3×13131112304112³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 123063162 + ... + 123169817.

It is an arithmetic number, because the mean of its divisors is an integer number (467153209656).

Almost surely, 2^{13131112304112} is an apocalyptic number.

13131112304112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13131112304112 is an abundant number, since it is smaller than the sum of its proper divisors (24241144468368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131112304112 is a wasteful number, since it uses less digits than its factorization.

13131112304112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 246233102 (or 246233096 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 13131112304112 its reverse (21140321113131), we get a palindrome (34271433417243).

The spelling of 13131112304112 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twelve million, three hundred four thousand, one hundred twelve".