Base | Representation |
---|---|
bin | 11101110110110101000110… |
… | …110111100100110011110100 |
3 | 122012221020012222111211102110 |
4 | 131312311012313210303310 |
5 | 114202400341333130140 |
6 | 1143135313225211020 |
7 | 36441631354606620 |
oct | 3566650667446364 |
9 | 565836188454373 |
10 | 131311224114420 |
11 | 38926860810739 |
12 | 12888bb3330a70 |
13 | 5836797b5533c |
14 | 245d6d62b6180 |
15 | 102aa8da7c380 |
hex | 776d46de4cf4 |
131311224114420 has 96 divisors (see below), whose sum is σ = 420198780024576. Its totient is φ = 30013789593600.
The previous prime is 131311224114341. The next prime is 131311224114509. The reversal of 131311224114420 is 24411422113131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65618260 + ... + 67589780.
It is an arithmetic number, because the mean of its divisors is an integer number (4377070625256).
Almost surely, 2131311224114420 is an apocalyptic number.
131311224114420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131311224114420 is an abundant number, since it is smaller than the sum of its proper divisors (288887555910156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311224114420 is a wasteful number, since it uses less digits than its factorization.
131311224114420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2130121 (or 2130119 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 131311224114420 its reverse (24411422113131), we get a palindrome (155722646227551).
The spelling of 131311224114420 in words is "one hundred thirty-one trillion, three hundred eleven billion, two hundred twenty-four million, one hundred fourteen thousand, four hundred twenty".
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