Base | Representation |
---|---|
bin | 11000011101010111… |
… | …00111001100000111 |
3 | 1020220010200212110101 |
4 | 30032223213030013 |
5 | 203343042344443 |
6 | 10010555304531 |
7 | 643255330321 |
oct | 141653471407 |
9 | 36803625411 |
10 | 13131215623 |
11 | 5629257719 |
12 | 266574b147 |
13 | 1313624896 |
14 | 8c7d64611 |
15 | 51cc2084d |
hex | 30eae7307 |
13131215623 has 2 divisors, whose sum is σ = 13131215624. Its totient is φ = 13131215622.
The previous prime is 13131215621. The next prime is 13131215639. The reversal of 13131215623 is 32651213131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (32651213131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13131215623 - 21 = 13131215621 is a prime.
Together with 13131215621, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13131215591 and 13131215600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131215621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565607811 + 6565607812.
It is an arithmetic number, because the mean of its divisors is an integer number (6565607812).
Almost surely, 213131215623 is an apocalyptic number.
13131215623 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131215623 is an equidigital number, since it uses as much as digits as its factorization.
13131215623 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3240, while the sum is 28.
Adding to 13131215623 its reverse (32651213131), we get a palindrome (45782428754).
The spelling of 13131215623 in words is "thirteen billion, one hundred thirty-one million, two hundred fifteen thousand, six hundred twenty-three".
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