13131251401140 has 144 divisors (see below), whose sum is σ = 40382686890000. Its totient is φ = 3453221044224.

The previous prime is 13131251401139. The next prime is 13131251401141. The reversal of 13131251401140 is 4110415213131.

13131251401140 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 1 + 2 + 514 + 0 + 1 + 140 = 666.

It is an interprime number because it is at equal distance from previous prime (13131251401139) and next prime (13131251401141).

It can be written as a sum of positive squares in 8 ways, for example, as 191245283856 + 12940006117284 = 437316^2 + 3597222^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131251401141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 100442536 + ... + 100573184.

It is an arithmetic number, because the mean of its divisors is an integer number (280435325625).

Almost surely, 2^{13131251401140} is an apocalyptic number.

13131251401140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13131251401140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20191343445000).

13131251401140 is an abundant number, since it is smaller than the sum of its proper divisors (27251435488860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131251401140 is a wasteful number, since it uses less digits than its factorization.

13131251401140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138386 (or 138381 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 13131251401140 its reverse (4110415213131), we get a palindrome (17241666614271).

The spelling of 13131251401140 in words is "thirteen trillion, one hundred thirty-one billion, two hundred fifty-one million, four hundred one thousand, one hundred forty".