Base | Representation |
---|---|
bin | 1011111100010110011001… |
… | …0101110101100001000010 |
3 | 1201111100112002001010201001 |
4 | 2333011212111311201002 |
5 | 3210121133044233010 |
6 | 43532255133002214 |
7 | 2523500061360250 |
oct | 277054625654102 |
9 | 51440462033631 |
10 | 13131432024130 |
11 | 4203011050842 |
12 | 1580b6202336a |
13 | 74339a441ab4 |
14 | 3357c977b5d0 |
15 | 17b8a30b8c3a |
hex | bf166575842 |
13131432024130 has 128 divisors (see below), whose sum is σ = 30114621573120. Its totient is φ = 4013417548800.
The previous prime is 13131432024127. The next prime is 13131432024131. The reversal of 13131432024130 is 3142023413131.
13131432024130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13131432024131) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 100571869 + ... + 100702351.
It is an arithmetic number, because the mean of its divisors is an integer number (235270481040).
Almost surely, 213131432024130 is an apocalyptic number.
13131432024130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13131432024130 is an abundant number, since it is smaller than the sum of its proper divisors (16983189548990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131432024130 is a wasteful number, since it uses less digits than its factorization.
13131432024130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134984.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13131432024130 its reverse (3142023413131), we get a palindrome (16273455437261).
The spelling of 13131432024130 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-two million, twenty-four thousand, one hundred thirty".
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