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13131523120147 is a prime number
BaseRepresentation
bin1011111100010110101111…
…0001010101110000010011
31201111100202102110021221121
42333011223301111300103
53210121324404321042
643532312145303111
72523502245566305
oct277055361256023
951440672407847
1013131523120147
114203058510603
121580b88634a97
137433b3288873
143357d78d1975
1517b8ab0b0367
hexbf16bc55c13

13131523120147 has 2 divisors, whose sum is σ = 13131523120148. Its totient is φ = 13131523120146.

The previous prime is 13131523120141. The next prime is 13131523120153. The reversal of 13131523120147 is 74102132513131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (13131523120141) and next prime (13131523120153).

It is a cyclic number.

It is not a de Polignac number, because 13131523120147 - 219 = 13131522595859 is a prime.

It is not a weakly prime, because it can be changed into another prime (13131523120141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565761560073 + 6565761560074.

It is an arithmetic number, because the mean of its divisors is an integer number (6565761560074).

Almost surely, 213131523120147 is an apocalyptic number.

13131523120147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131523120147 is an equidigital number, since it uses as much as digits as its factorization.

13131523120147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 13131523120147 its reverse (74102132513131), we get a palindrome (87233655633278).

The spelling of 13131523120147 in words is "thirteen trillion, one hundred thirty-one billion, five hundred twenty-three million, one hundred twenty thousand, one hundred forty-seven".