Base | Representation |
---|---|
bin | 11101110110111101100100… |
… | …000001100101110101001101 |
3 | 122012222002122201102212112012 |
4 | 131312331210001211311031 |
5 | 114203022440110321101 |
6 | 1143143414153551005 |
7 | 36442402350643454 |
oct | 3566754401456515 |
9 | 565862581385465 |
10 | 131320303213901 |
11 | 3892a69a71853a |
12 | 1288a907a15465 |
13 | 58375b3b0bb59 |
14 | 245dd17ddbb9b |
15 | 102ae20b80bbb |
hex | 776f64065d4d |
131320303213901 has 2 divisors, whose sum is σ = 131320303213902. Its totient is φ = 131320303213900.
The previous prime is 131320303213843. The next prime is 131320303213903. The reversal of 131320303213901 is 109312303023131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69201851125225 + 62118452088676 = 8318765^2 + 7881526^2 .
It is a cyclic number.
It is not a de Polignac number, because 131320303213901 - 210 = 131320303212877 is a prime.
Together with 131320303213903, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131320303213903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660151606950 + 65660151606951.
It is an arithmetic number, because the mean of its divisors is an integer number (65660151606951).
Almost surely, 2131320303213901 is an apocalyptic number.
It is an amenable number.
131320303213901 is a deficient number, since it is larger than the sum of its proper divisors (1).
131320303213901 is an equidigital number, since it uses as much as digits as its factorization.
131320303213901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 32.
The spelling of 131320303213901 in words is "one hundred thirty-one trillion, three hundred twenty billion, three hundred three million, two hundred thirteen thousand, nine hundred one".
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