1313211131957 has 2 divisors, whose sum is σ = 1313211131958. Its totient is φ = 1313211131956.

The previous prime is 1313211131941. The next prime is 1313211132017. The reversal of 1313211131957 is 7591311123131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1161579550756 + 151631581201 = 1077766^2 + 389399^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313211131957 - 2⁴ = 1313211131941 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1313211131957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313211131917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656605565978 + 656605565979.

It is an arithmetic number, because the mean of its divisors is an integer number (656605565979).

Almost surely, 2^{1313211131957} is an apocalyptic number.

It is an amenable number.

1313211131957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313211131957 is an equidigital number, since it uses as much as digits as its factorization.

1313211131957 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17010, while the sum is 38.

The spelling of 1313211131957 in words is "one trillion, three hundred thirteen billion, two hundred eleven million, one hundred thirty-one thousand, nine hundred fifty-seven".