13132433141143 has 2 divisors, whose sum is σ = 13132433141144. Its totient is φ = 13132433141142.

The previous prime is 13132433141119. The next prime is 13132433141167. The reversal of 13132433141143 is 34114133423131.

13132433141143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13132433141119) and next prime (13132433141167).

It is an emirp because it is prime and its reverse (34114133423131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13132433141143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13132433141099 and 13132433141108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13132433741143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566216570571 + 6566216570572.

It is an arithmetic number, because the mean of its divisors is an integer number (6566216570572).

Almost surely, 2^{13132433141143} is an apocalyptic number.

13132433141143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132433141143 is an equidigital number, since it uses as much as digits as its factorization.

13132433141143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 34.

Adding to 13132433141143 its reverse (34114133423131), we get a palindrome (47246566564274).

The spelling of 13132433141143 in words is "thirteen trillion, one hundred thirty-two billion, four hundred thirty-three million, one hundred forty-one thousand, one hundred forty-three".