Base | Representation |
---|---|
bin | 11101110111001000000000… |
… | …110010011101001110101011 |
3 | 122020000011121122211102110110 |
4 | 131313020000302131032223 |
5 | 114203213424420012021 |
6 | 1143152511401145403 |
7 | 36443250401202054 |
oct | 3567100062351653 |
9 | 566004548742413 |
10 | 131331523204011 |
11 | 38934428052139 |
12 | 12890b1948b263 |
13 | 583868149c560 |
14 | 24606a01b572b |
15 | 102b37abc7476 |
hex | 777200c9d3ab |
131331523204011 has 64 divisors (see below), whose sum is σ = 202477187759616. Its totient is φ = 75003863500800.
The previous prime is 131331523203971. The next prime is 131331523204019. The reversal of 131331523204011 is 110402325133131.
It is not a de Polignac number, because 131331523204011 - 213 = 131331523195819 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131331523204011.
It is not an unprimeable number, because it can be changed into a prime (131331523204019) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8820276 + ... + 18451566.
It is an arithmetic number, because the mean of its divisors is an integer number (3163706058744).
Almost surely, 2131331523204011 is an apocalyptic number.
131331523204011 is a deficient number, since it is larger than the sum of its proper divisors (71145664555605).
131331523204011 is a wasteful number, since it uses less digits than its factorization.
131331523204011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9631612.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 131331523204011 its reverse (110402325133131), we get a palindrome (241733848337142).
The spelling of 131331523204011 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, five hundred twenty-three million, two hundred four thousand, eleven".
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