Base | Representation |
---|---|
bin | 111101001010001111… |
… | …0110011000001010111 |
3 | 110120000022121101212111 |
4 | 1322110132303001113 |
5 | 4122441032321101 |
6 | 140200430331451 |
7 | 12326505413122 |
oct | 1722436630127 |
9 | 416008541774 |
10 | 131340120151 |
11 | 5077908a249 |
12 | 21555659b87 |
13 | c501718c36 |
14 | 64dd4713b9 |
15 | 363a82b251 |
hex | 1e947b3057 |
131340120151 has 2 divisors, whose sum is σ = 131340120152. Its totient is φ = 131340120150.
The previous prime is 131340120097. The next prime is 131340120173. The reversal of 131340120151 is 151021043131.
It is a happy number.
It is an a-pointer prime, because the next prime (131340120173) can be obtained adding 131340120151 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131340120151 - 211 = 131340118103 is a prime.
It is a super-2 number, since 2×1313401201512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131340120181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65670060075 + 65670060076.
It is an arithmetic number, because the mean of its divisors is an integer number (65670060076).
Almost surely, 2131340120151 is an apocalyptic number.
131340120151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131340120151 is an equidigital number, since it uses as much as digits as its factorization.
131340120151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 131340120151 its reverse (151021043131), we get a palindrome (282361163282).
The spelling of 131340120151 in words is "one hundred thirty-one billion, three hundred forty million, one hundred twenty thousand, one hundred fifty-one".
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