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1313425644317 is a prime number
BaseRepresentation
bin10011000111001110010…
…001001101101100011101
311122120011220001211220222
4103013032101031230131
5133004343431104232
62443213541451125
7163614624525503
oct23071621155435
94576156054828
101313425644317
11467025598506
12192673710aa5
1396b17718c87
14477da672673
1524272903d12
hex131ce44db1d

1313425644317 has 2 divisors, whose sum is σ = 1313425644318. Its totient is φ = 1313425644316.

The previous prime is 1313425644287. The next prime is 1313425644347. The reversal of 1313425644317 is 7134465243131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1313425644287) and next prime (1313425644347).

It can be written as a sum of positive squares in only one way, i.e., 1194887285881 + 118538358436 = 1093109^2 + 344294^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313425644317 - 28 = 1313425644061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313425644347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656712822158 + 656712822159.

It is an arithmetic number, because the mean of its divisors is an integer number (656712822159).

Almost surely, 21313425644317 is an apocalyptic number.

It is an amenable number.

1313425644317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313425644317 is an equidigital number, since it uses as much as digits as its factorization.

1313425644317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 725760, while the sum is 44.

The spelling of 1313425644317 in words is "one trillion, three hundred thirteen billion, four hundred twenty-five million, six hundred forty-four thousand, three hundred seventeen".