1313427130040 has 32 divisors (see below), whose sum is σ = 2955947813280. Its totient is φ = 525239870592.

The previous prime is 1313427129979. The next prime is 1313427130121. The reversal of 1313427130040 is 400317243131.

It is a super-2 number, since 2×1313427130040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313427129985 and 1313427130012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3930644 + ... + 4251683.

It is an arithmetic number, because the mean of its divisors is an integer number (92373369165).

Almost surely, 2^{1313427130040} is an apocalyptic number.

1313427130040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313427130040 is an abundant number, since it is smaller than the sum of its proper divisors (1642520683240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313427130040 is a wasteful number, since it uses less digits than its factorization.

1313427130040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8186351 (or 8186347 counting only the distinct ones).

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 1313427130040 in words is "one trillion, three hundred thirteen billion, four hundred twenty-seven million, one hundred thirty thousand, forty".