131343220010440 has 64 divisors (see below), whose sum is σ = 317576144016000. Its totient is φ = 48708846455808.

The previous prime is 131343220010437. The next prime is 131343220010447. The reversal of 131343220010440 is 44010022343131.

It is a happy number.

131343220010440 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 131343220010399 and 131343220010408.

It is not an unprimeable number, because it can be changed into a prime (131343220010447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1441385740 + ... + 1441476859.

It is an arithmetic number, because the mean of its divisors is an integer number (4962127250250).

Almost surely, 2^{131343220010440} is an apocalyptic number.

131343220010440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131343220010440 is an abundant number, since it is smaller than the sum of its proper divisors (186232924005560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131343220010440 is a wasteful number, since it uses less digits than its factorization.

131343220010440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2882862694 (or 2882862690 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 131343220010440 its reverse (44010022343131), we get a palindrome (175353242353571).

The spelling of 131343220010440 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred twenty million, ten thousand, four hundred forty".