131350415345550 has 72 divisors (see below), whose sum is σ = 353058086787120. Its totient is φ = 35010568569600.

The previous prime is 131350415345549. The next prime is 131350415345749. The reversal of 131350415345550 is 55543514053131.

131350415345550 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 5 + 0 + 4 + 1 + 53 + 45 + 550 = 666.

It is a super-2 number, since 2×131350415345550² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a junction number, because it is equal to n+sod(n) for n = 131350415345496 and 131350415345505.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 66563370 + ... + 68508269.

It is an arithmetic number, because the mean of its divisors is an integer number (4903584538710).

Almost surely, 2^{131350415345550} is an apocalyptic number.

131350415345550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131350415345550 is an abundant number, since it is smaller than the sum of its proper divisors (221707671441570).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131350415345550 is a wasteful number, since it uses less digits than its factorization.

131350415345550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135073818 (or 135073810 counting only the distinct ones).

The product of its (nonzero) digits is 1350000, while the sum is 45.

Adding to 131350415345550 its reverse (55543514053131), we get a palindrome (186893929398681).

The spelling of 131350415345550 in words is "one hundred thirty-one trillion, three hundred fifty billion, four hundred fifteen million, three hundred forty-five thousand, five hundred fifty".