Base | Representation |
---|---|
bin | 111101001010100111… |
… | …0000100101011000101 |
3 | 110120001011221000222002 |
4 | 1322111032010223011 |
5 | 4123002220410341 |
6 | 140201552115045 |
7 | 12330015640406 |
oct | 1722516045305 |
9 | 416034830862 |
10 | 131352513221 |
11 | 50785084356 |
12 | 21559835a85 |
13 | c504167b07 |
14 | 6500d799ad |
15 | 363b97829b |
hex | 1e95384ac5 |
131352513221 has 2 divisors, whose sum is σ = 131352513222. Its totient is φ = 131352513220.
The previous prime is 131352513209. The next prime is 131352513223. The reversal of 131352513221 is 122315253131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128082388996 + 3270124225 = 357886^2 + 57185^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131352513221 is a prime.
Together with 131352513223, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131352513223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65676256610 + 65676256611.
It is an arithmetic number, because the mean of its divisors is an integer number (65676256611).
Almost surely, 2131352513221 is an apocalyptic number.
It is an amenable number.
131352513221 is a deficient number, since it is larger than the sum of its proper divisors (1).
131352513221 is an equidigital number, since it uses as much as digits as its factorization.
131352513221 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
Adding to 131352513221 its reverse (122315253131), we get a palindrome (253667766352).
The spelling of 131352513221 in words is "one hundred thirty-one billion, three hundred fifty-two million, five hundred thirteen thousand, two hundred twenty-one".
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