Base | Representation |
---|---|
bin | 111101001010100111… |
… | …0000100101011000111 |
3 | 110120001011221000222011 |
4 | 1322111032010223013 |
5 | 4123002220410343 |
6 | 140201552115051 |
7 | 12330015640411 |
oct | 1722516045307 |
9 | 416034830864 |
10 | 131352513223 |
11 | 50785084358 |
12 | 21559835a87 |
13 | c504167b09 |
14 | 6500d799b1 |
15 | 363b97829d |
hex | 1e95384ac7 |
131352513223 has 2 divisors, whose sum is σ = 131352513224. Its totient is φ = 131352513222.
The previous prime is 131352513221. The next prime is 131352513247. The reversal of 131352513223 is 322315253131.
It is a weak prime.
It is an emirp because it is prime and its reverse (322315253131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131352513223 - 21 = 131352513221 is a prime.
Together with 131352513221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131352513221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65676256611 + 65676256612.
It is an arithmetic number, because the mean of its divisors is an integer number (65676256612).
Almost surely, 2131352513223 is an apocalyptic number.
131352513223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131352513223 is an equidigital number, since it uses as much as digits as its factorization.
131352513223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 31.
Adding to 131352513223 its reverse (322315253131), we get a palindrome (453667766354).
The spelling of 131352513223 in words is "one hundred thirty-one billion, three hundred fifty-two million, five hundred thirteen thousand, two hundred twenty-three".
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