Base | Representation |
---|---|
bin | 11000011110010111… |
… | …10010101011100100 |
3 | 1020220201120110000212 |
4 | 30033023302223210 |
5 | 203402222320200 |
6 | 10011500154552 |
7 | 643420123166 |
oct | 141713625344 |
9 | 36821513025 |
10 | 13139651300 |
11 | 5632a99556 |
12 | 2668538a58 |
13 | 13152b93c9 |
14 | 8c911c936 |
15 | 51d83a035 |
hex | 30f2f2ae4 |
13139651300 has 144 divisors (see below), whose sum is σ = 29923084800. Its totient is φ = 5003980800.
The previous prime is 13139651293. The next prime is 13139651309. The reversal of 13139651300 is 315693131.
It is a super-3 number, since 3×131396513003 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13139651309) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 36600521 + ... + 36600879.
It is an arithmetic number, because the mean of its divisors is an integer number (207799200).
Almost surely, 213139651300 is an apocalyptic number.
13139651300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13139651300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14961542400).
13139651300 is an abundant number, since it is smaller than the sum of its proper divisors (16783433500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13139651300 is a wasteful number, since it uses less digits than its factorization.
13139651300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606 (or 599 counting only the distinct ones).
The product of its (nonzero) digits is 7290, while the sum is 32.
The spelling of 13139651300 in words is "thirteen billion, one hundred thirty-nine million, six hundred fifty-one thousand, three hundred".
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