Base | Representation |
---|---|
bin | 11101111000001010100111… |
… | …000011101101100101011111 |
3 | 122020021000012020122220220221 |
4 | 131320022213003231211133 |
5 | 114210401402222101142 |
6 | 1143245415235422211 |
7 | 36451361430626155 |
oct | 3570124703554537 |
9 | 566230166586827 |
10 | 131403032222047 |
11 | 38961793023853 |
12 | 128a2955754967 |
13 | 5842339445a91 |
14 | 2463d2539b3d5 |
15 | 102d163a14767 |
hex | 7782a70ed95f |
131403032222047 has 2 divisors, whose sum is σ = 131403032222048. Its totient is φ = 131403032222046.
The previous prime is 131403032222017. The next prime is 131403032222081. The reversal of 131403032222047 is 740222230304131.
It is an a-pointer prime, because the next prime (131403032222081) can be obtained adding 131403032222047 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131403032222047 - 215 = 131403032189279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131403032222017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701516111023 + 65701516111024.
It is an arithmetic number, because the mean of its divisors is an integer number (65701516111024).
Almost surely, 2131403032222047 is an apocalyptic number.
131403032222047 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403032222047 is an equidigital number, since it uses as much as digits as its factorization.
131403032222047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 131403032222047 its reverse (740222230304131), we get a palindrome (871625262526178).
The spelling of 131403032222047 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-two million, two hundred twenty-two thousand, forty-seven".
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