Base | Representation |
---|---|
bin | 11101111000001010111010… |
… | …010001010011111100010010 |
3 | 122020021001000201012002102020 |
4 | 131320022322101103330102 |
5 | 114210403032231213010 |
6 | 1143245511232232310 |
7 | 36451402423456641 |
oct | 3570127221237422 |
9 | 566231021162366 |
10 | 131403354554130 |
11 | 38961938a706aa |
12 | 128a2a2569b696 |
13 | 584238b162619 |
14 | 2463d56105358 |
15 | 102d181e85470 |
hex | 7782ba453f12 |
131403354554130 has 32 divisors (see below), whose sum is σ = 318619267956864. Its totient is φ = 34679648211456.
The previous prime is 131403354554113. The next prime is 131403354554179. The reversal of 131403354554130 is 31455453304131.
131403354554130 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1314033545541302 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22577893062 + ... + 22577898881.
It is an arithmetic number, because the mean of its divisors is an integer number (9956852123652).
Almost surely, 2131403354554130 is an apocalyptic number.
131403354554130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131403354554130 is an abundant number, since it is smaller than the sum of its proper divisors (187215913402734).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131403354554130 is a wasteful number, since it uses less digits than its factorization.
131403354554130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45155792050.
The product of its (nonzero) digits is 648000, while the sum is 42.
The spelling of 131403354554130 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred fifty-four million, five hundred fifty-four thousand, one hundred thirty".
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