131403430255040 has 28 divisors (see below), whose sum is σ = 312904418295576. Its totient is φ = 52561372101888.

The previous prime is 131403430255001. The next prime is 131403430255043. The reversal of 131403430255040 is 40552034304131.

It is a super-2 number, since 2×131403430255040² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131403430255043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205317859454 + ... + 205317860093.

Almost surely, 2^{131403430255040} is an apocalyptic number.

131403430255040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131403430255040 is an abundant number, since it is smaller than the sum of its proper divisors (181500988040536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131403430255040 is an equidigital number, since it uses as much as digits as its factorization.

131403430255040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410635719564 (or 410635719554 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 131403430255040 its reverse (40552034304131), we get a palindrome (171955464559171).

The spelling of 131403430255040 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty million, two hundred fifty-five thousand, forty".