Base | Representation |
---|---|
bin | 1011111100110111100101… |
… | …1110111010001101011110 |
3 | 1201112012112002210220201012 |
4 | 2333031321132322031132 |
5 | 3210242410313314400 |
6 | 43540331300215222 |
7 | 2524233644325050 |
oct | 277157136721536 |
9 | 51465462726635 |
10 | 13140343104350 |
11 | 4206874129250 |
12 | 158282a39a512 |
13 | 74418a65aa27 |
14 | 335dd30478d0 |
15 | 17bc2557dd35 |
hex | bf3797ba35e |
13140343104350 has 48 divisors (see below), whose sum is σ = 30471943706496. Its totient is φ = 4095691356000.
The previous prime is 13140343104349. The next prime is 13140343104389. The reversal of 13140343104350 is 5340134304131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1706534216 + ... + 1706541915.
It is an arithmetic number, because the mean of its divisors is an integer number (634832160552).
Almost surely, 213140343104350 is an apocalyptic number.
13140343104350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140343104350 is an abundant number, since it is smaller than the sum of its proper divisors (17331600602146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140343104350 is a wasteful number, since it uses less digits than its factorization.
13140343104350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3413076161 (or 3413076156 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 13140343104350 its reverse (5340134304131), we get a palindrome (18480477408481).
The spelling of 13140343104350 in words is "thirteen trillion, one hundred forty billion, three hundred forty-three million, one hundred four thousand, three hundred fifty".
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