131404024421240 has 128 divisors (see below), whose sum is σ = 304095914496000. Its totient is φ = 51074407802880.

The previous prime is 131404024421233. The next prime is 131404024421279. The reversal of 131404024421240 is 42124420404131.

It is a junction number, because it is equal to n+sod(n) for n = 131404024421197 and 131404024421206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3094532249 + ... + 3094574711.

It is an arithmetic number, because the mean of its divisors is an integer number (2375749332000).

Almost surely, 2^{131404024421240} is an apocalyptic number.

131404024421240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131404024421240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152047957248000).

131404024421240 is an abundant number, since it is smaller than the sum of its proper divisors (172691890074760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131404024421240 is a wasteful number, since it uses less digits than its factorization.

131404024421240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51757 (or 51753 counting only the distinct ones).

The product of its (nonzero) digits is 24576, while the sum is 32.

Adding to 131404024421240 its reverse (42124420404131), we get a palindrome (173528444825371).

The spelling of 131404024421240 in words is "one hundred thirty-one trillion, four hundred four billion, twenty-four million, four hundred twenty-one thousand, two hundred forty".