Base | Representation |
---|---|
bin | 11000011110100010… |
… | …00110011110110100 |
3 | 1020220211012011020220 |
4 | 30033101012132310 |
5 | 203403101334444 |
6 | 10011550054340 |
7 | 643435011036 |
oct | 141721063664 |
9 | 36824164226 |
10 | 13141043124 |
11 | 563385a220 |
12 | 2668aaa3b0 |
13 | 1315685a81 |
14 | 8c93a1c56 |
15 | 51da12619 |
hex | 30f4467b4 |
13141043124 has 48 divisors (see below), whose sum is σ = 33949203456. Its totient is φ = 3922696800.
The previous prime is 13141043117. The next prime is 13141043141. The reversal of 13141043124 is 42134014131.
13141043124 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13141043094 and 13141043103.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 734092 + ... + 751779.
It is an arithmetic number, because the mean of its divisors is an integer number (707275072).
Almost surely, 213141043124 is an apocalyptic number.
It is an amenable number.
13141043124 is an abundant number, since it is smaller than the sum of its proper divisors (20808160332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13141043124 is a wasteful number, since it uses less digits than its factorization.
13141043124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1485956 (or 1485954 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13141043124 its reverse (42134014131), we get a palindrome (55275057255).
The spelling of 13141043124 in words is "thirteen billion, one hundred forty-one million, forty-three thousand, one hundred twenty-four".
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