131413111432301 has 2 divisors, whose sum is σ = 131413111432302. Its totient is φ = 131413111432300.

The previous prime is 131413111432243. The next prime is 131413111432303. The reversal of 131413111432301 is 103234111314131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126995657485225 + 4417453947076 = 11269235^2 + 2101774^2 .

It is a cyclic number.

It is not a de Polignac number, because 131413111432301 - 2¹⁴ = 131413111415917 is a prime.

Together with 131413111432303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131413111432303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706555716150 + 65706555716151.

It is an arithmetic number, because the mean of its divisors is an integer number (65706555716151).

Almost surely, 2^{131413111432301} is an apocalyptic number.

It is an amenable number.

131413111432301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131413111432301 is an equidigital number, since it uses as much as digits as its factorization.

131413111432301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 131413111432301 its reverse (103234111314131), we get a palindrome (234647222746432).

The spelling of 131413111432301 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred eleven million, four hundred thirty-two thousand, three hundred one".