131420451224441 has 2 divisors, whose sum is σ = 131420451224442. Its totient is φ = 131420451224440.

The previous prime is 131420451224411. The next prime is 131420451224443. The reversal of 131420451224441 is 144422154024131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127875500322025 + 3544950902416 = 11308205^2 + 1882804^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131420451224441 is a prime.

It is a super-3 number, since 3×131420451224441³ (a number of 43 digits) contains 333 as substring.

Together with 131420451224443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131420451224395 and 131420451224404.

It is not a weakly prime, because it can be changed into another prime (131420451224443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65710225612220 + 65710225612221.

It is an arithmetic number, because the mean of its divisors is an integer number (65710225612221).

Almost surely, 2^{131420451224441} is an apocalyptic number.

It is an amenable number.

131420451224441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131420451224441 is an equidigital number, since it uses as much as digits as its factorization.

131420451224441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122880, while the sum is 38.

The spelling of 131420451224441 in words is "one hundred thirty-one trillion, four hundred twenty billion, four hundred fifty-one million, two hundred twenty-four thousand, four hundred forty-one".