Base | Representation |
---|---|
bin | 10011001000000110101… |
… | …000010001110001111111 |
3 | 11122122121210022210022111 |
4 | 103020012220101301333 |
5 | 133013313012330323 |
6 | 2443451440354451 |
7 | 163650225661666 |
oct | 23100650216177 |
9 | 4578553283274 |
10 | 1314371214463 |
11 | 46747031533a |
12 | 192898315a27 |
13 | 96c385a9638 |
14 | 4788a091ddd |
15 | 242ca932c0d |
hex | 13206a11c7f |
1314371214463 has 2 divisors, whose sum is σ = 1314371214464. Its totient is φ = 1314371214462.
The previous prime is 1314371214461. The next prime is 1314371214473. The reversal of 1314371214463 is 3644121734131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314371214463 - 21 = 1314371214461 is a prime.
Together with 1314371214461, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314371214461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657185607231 + 657185607232.
It is an arithmetic number, because the mean of its divisors is an integer number (657185607232).
Almost surely, 21314371214463 is an apocalyptic number.
1314371214463 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314371214463 is an equidigital number, since it uses as much as digits as its factorization.
1314371214463 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 145152, while the sum is 40.
Adding to 1314371214463 its reverse (3644121734131), we get a palindrome (4958492948594).
The spelling of 1314371214463 in words is "one trillion, three hundred fourteen billion, three hundred seventy-one million, two hundred fourteen thousand, four hundred sixty-three".
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