1314371214461 has 2 divisors, whose sum is σ = 1314371214462. Its totient is φ = 1314371214460.

The previous prime is 1314371214439. The next prime is 1314371214463. The reversal of 1314371214461 is 1644121734131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 698979602500 + 615391611961 = 836050^2 + 784469^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1314371214461 is a prime.

Together with 1314371214463, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314371214463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657185607230 + 657185607231.

It is an arithmetic number, because the mean of its divisors is an integer number (657185607231).

Almost surely, 2^{1314371214461} is an apocalyptic number.

It is an amenable number.

1314371214461 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314371214461 is an equidigital number, since it uses as much as digits as its factorization.

1314371214461 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48384, while the sum is 38.

Adding to 1314371214461 its reverse (1644121734131), we get a palindrome (2958492948592).

The spelling of 1314371214461 in words is "one trillion, three hundred fourteen billion, three hundred seventy-one million, two hundred fourteen thousand, four hundred sixty-one".