Base | Representation |
---|---|
bin | 10011001000101000001… |
… | …101100111011001011101 |
3 | 11122201002001112022012102 |
4 | 103020220031213121131 |
5 | 133020441232303321 |
6 | 2444023405014445 |
7 | 164000210053355 |
oct | 23105015473135 |
9 | 4581061468172 |
10 | 1314934650461 |
11 | 46772a36a123 |
12 | 192a14b54425 |
13 | 96cc8242613 |
14 | 47900c3bb65 |
15 | 2431012bc0b |
hex | 1322836765d |
1314934650461 has 2 divisors, whose sum is σ = 1314934650462. Its totient is φ = 1314934650460.
The previous prime is 1314934650433. The next prime is 1314934650487. The reversal of 1314934650461 is 1640564394131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1314934650436 + 25 = 1146706^2 + 5^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314934650461 - 222 = 1314930456157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314934650401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657467325230 + 657467325231.
It is an arithmetic number, because the mean of its divisors is an integer number (657467325231).
Almost surely, 21314934650461 is an apocalyptic number.
It is an amenable number.
1314934650461 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314934650461 is an equidigital number, since it uses as much as digits as its factorization.
1314934650461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 47.
The spelling of 1314934650461 in words is "one trillion, three hundred fourteen billion, nine hundred thirty-four million, six hundred fifty thousand, four hundred sixty-one".
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