131501616732557 has 2 divisors, whose sum is σ = 131501616732558. Its totient is φ = 131501616732556.

The previous prime is 131501616732427. The next prime is 131501616732559. The reversal of 131501616732557 is 755237616105131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131211274653001 + 290342079556 = 11454749^2 + 538834^2 .

It is a cyclic number.

It is not a de Polignac number, because 131501616732557 - 2³⁸ = 131226738825613 is a prime.

Together with 131501616732559, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131501616732499 and 131501616732508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131501616732559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65750808366278 + 65750808366279.

It is an arithmetic number, because the mean of its divisors is an integer number (65750808366279).

Almost surely, 2^{131501616732557} is an apocalyptic number.

It is an amenable number.

131501616732557 is a deficient number, since it is larger than the sum of its proper divisors (1).

131501616732557 is an equidigital number, since it uses as much as digits as its factorization.

131501616732557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3969000, while the sum is 53.

The spelling of 131501616732557 in words is "one hundred thirty-one trillion, five hundred one billion, six hundred sixteen million, seven hundred thirty-two thousand, five hundred fifty-seven".