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1315225874717 is a prime number
BaseRepresentation
bin10011001000111001100…
…100100011000100011101
311122201211100112000202222
4103020321210203010131
5133022040310442332
62444112330555125
7164010344322566
oct23107144430435
94581740460688
101315225874717
1146786979a227
12192a96598aa5
1397043689b71
144792b7a916d
152432a9a5712
hex1323992311d

1315225874717 has 2 divisors, whose sum is σ = 1315225874718. Its totient is φ = 1315225874716.

The previous prime is 1315225874659. The next prime is 1315225874719. The reversal of 1315225874717 is 7174785225131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 783943784836 + 531282089881 = 885406^2 + 728891^2 .

It is an emirp because it is prime and its reverse (7174785225131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1315225874717 - 218 = 1315225612573 is a prime.

Together with 1315225874719, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315225874719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657612937358 + 657612937359.

It is an arithmetic number, because the mean of its divisors is an integer number (657612937359).

Almost surely, 21315225874717 is an apocalyptic number.

It is an amenable number.

1315225874717 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315225874717 is an equidigital number, since it uses as much as digits as its factorization.

1315225874717 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3292800, while the sum is 53.

The spelling of 1315225874717 in words is "one trillion, three hundred fifteen billion, two hundred twenty-five million, eight hundred seventy-four thousand, seven hundred seventeen".