Base | Representation |
---|---|
bin | 10011001001000000100… |
… | …101000100000001011000 |
3 | 11122202010112202111000111 |
4 | 103021000211010001120 |
5 | 133022310410401300 |
6 | 2444132131014104 |
7 | 164013302565343 |
oct | 23110045040130 |
9 | 4582115674014 |
10 | 1315343450200 |
11 | 46791a0a544a |
12 | 192b09a3a334 |
13 | 97061b45360 |
14 | 4793d25345a |
15 | 24335e7c9ba |
hex | 13240944058 |
1315343450200 has 48 divisors (see below), whose sum is σ = 3293417645280. Its totient is φ = 485665272960.
The previous prime is 1315343450129. The next prime is 1315343450219. The reversal of 1315343450200 is 20543435131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 252948064 + ... + 252953263.
It is an arithmetic number, because the mean of its divisors is an integer number (68612867610).
Almost surely, 21315343450200 is an apocalyptic number.
1315343450200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1315343450200 is an abundant number, since it is smaller than the sum of its proper divisors (1978074195080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1315343450200 is a wasteful number, since it uses less digits than its factorization.
1315343450200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505901356 (or 505901347 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1315343450200 its reverse (20543435131), we get a palindrome (1335886885331).
The spelling of 1315343450200 in words is "one trillion, three hundred fifteen billion, three hundred forty-three million, four hundred fifty thousand, two hundred".
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