Base | Representation |
---|---|
bin | 1011111101101000110001… |
… | …0110001111100000110100 |
3 | 1201120110121010120100211222 |
4 | 2333122030112033200310 |
5 | 3211001424343020200 |
6 | 43550353244045512 |
7 | 2525212044335600 |
oct | 277321426174064 |
9 | 51513533510758 |
10 | 13153544501300 |
11 | 4211428a60165 |
12 | 15852b3533898 |
13 | 7454b2685808 |
14 | 3368c643a500 |
15 | 17c249513d85 |
hex | bf68c58f834 |
13153544501300 has 108 divisors (see below), whose sum is σ = 33206976078444. Its totient is φ = 4509288000000.
The previous prime is 13153544501291. The next prime is 13153544501303. The reversal of 13153544501300 is 310544535131.
It can be written as a sum of positive squares in 6 ways, for example, as 23226979216 + 13130317522084 = 152404^2 + 3623578^2 .
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13153544501303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 45607550 + ... + 45895050.
Almost surely, 213153544501300 is an apocalyptic number.
13153544501300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13153544501300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16603488039222).
13153544501300 is an abundant number, since it is smaller than the sum of its proper divisors (20053431577144).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13153544501300 is a wasteful number, since it uses less digits than its factorization.
13153544501300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 296866 (or 296852 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 13153544501300 in words is "thirteen trillion, one hundred fifty-three billion, five hundred forty-four million, five hundred one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •