Base | Representation |
---|---|
bin | 1011111101101110011100… |
… | …0101000110010111110110 |
3 | 1201120121112012220210122110 |
4 | 2333123213011012113312 |
5 | 3211013034040442240 |
6 | 43551204302511450 |
7 | 2525264550162162 |
oct | 277334705062766 |
9 | 51517465823573 |
10 | 13155066734070 |
11 | 421203a246178 |
12 | 1585659295586 |
13 | 745695b60571 |
14 | 3369cc689ca2 |
15 | 17c2d7ea0c80 |
hex | bf6e71465f6 |
13155066734070 has 128 divisors (see below), whose sum is σ = 32718921079680. Its totient is φ = 3381034496000.
The previous prime is 13155066734063. The next prime is 13155066734081. The reversal of 13155066734070 is 7043766055131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2291421400 + ... + 2291427140.
It is an arithmetic number, because the mean of its divisors is an integer number (255616570935).
Almost surely, 213155066734070 is an apocalyptic number.
13155066734070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13155066734070, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16359460539840).
13155066734070 is an abundant number, since it is smaller than the sum of its proper divisors (19563854345610).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13155066734070 is a wasteful number, since it uses less digits than its factorization.
13155066734070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10002.
The product of its (nonzero) digits is 1587600, while the sum is 48.
The spelling of 13155066734070 in words is "thirteen trillion, one hundred fifty-five billion, sixty-six million, seven hundred thirty-four thousand, seventy".
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