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131565256126093 is a prime number
BaseRepresentation
bin11101111010100001101100…
…010110110010111010001101
3122020211111220220120002202101
4131322201230112302322031
5114221031121032013333
61143452124432555101
736466163460230506
oct3572415426627215
9566744826502671
10131565256126093
1138a1456a202a39
121290a28a0b2a91
13585472036344a
14246bb143b1bad
1510324aa84167d
hex77a86c5b2e8d

131565256126093 has 2 divisors, whose sum is σ = 131565256126094. Its totient is φ = 131565256126092.

The previous prime is 131565256126091. The next prime is 131565256126141. The reversal of 131565256126093 is 390621652565131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130361886617769 + 1203369508324 = 11417613^2 + 1096982^2 .

It is a cyclic number.

It is not a de Polignac number, because 131565256126093 - 21 = 131565256126091 is a prime.

Together with 131565256126091, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131565256126091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65782628063046 + 65782628063047.

It is an arithmetic number, because the mean of its divisors is an integer number (65782628063047).

Almost surely, 2131565256126093 is an apocalyptic number.

It is an amenable number.

131565256126093 is a deficient number, since it is larger than the sum of its proper divisors (1).

131565256126093 is an equidigital number, since it uses as much as digits as its factorization.

131565256126093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748000, while the sum is 55.

The spelling of 131565256126093 in words is "one hundred thirty-one trillion, five hundred sixty-five billion, two hundred fifty-six million, one hundred twenty-six thousand, ninety-three".