Base | Representation |
---|---|
bin | 1011111101110111001100… |
… | …0001111100011100000110 |
3 | 1201120211120212001200222020 |
4 | 2333131303001330130012 |
5 | 3211032341131422230 |
6 | 43552233300144010 |
7 | 2525410000541052 |
oct | 277356301743406 |
9 | 51524525050866 |
10 | 13157414717190 |
11 | 421303465a697 |
12 | 1585bb3698006 |
13 | 74597b435aa3 |
14 | 336b72448c62 |
15 | 17c3c419e810 |
hex | bf77307c706 |
13157414717190 has 64 divisors (see below), whose sum is σ = 31755038357952. Its totient is φ = 3488953651200.
The previous prime is 13157414717177. The next prime is 13157414717299. The reversal of 13157414717190 is 9171741475131.
It is a super-3 number, since 3×131574147171903 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65673570 + ... + 65873610.
It is an arithmetic number, because the mean of its divisors is an integer number (496172474343).
Almost surely, 213157414717190 is an apocalyptic number.
13157414717190 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13157414717190 is an abundant number, since it is smaller than the sum of its proper divisors (18597623640762).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13157414717190 is a wasteful number, since it uses less digits than its factorization.
13157414717190 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212345.
The product of its (nonzero) digits is 740880, while the sum is 51.
The spelling of 13157414717190 in words is "thirteen trillion, one hundred fifty-seven billion, four hundred fourteen million, seven hundred seventeen thousand, one hundred ninety".
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