Base | Representation |
---|---|
bin | 11000100000011111… |
… | …10100011011011101 |
3 | 1020221222010110020121 |
4 | 30100033310123131 |
5 | 203421303444003 |
6 | 10013334314541 |
7 | 644024525254 |
oct | 142017643335 |
9 | 36858113217 |
10 | 13157484253 |
11 | 5642069731 |
12 | 26724b8a51 |
13 | 1318bc1354 |
14 | 8cb64179b |
15 | 5201adcbd |
hex | 3103f46dd |
13157484253 has 2 divisors, whose sum is σ = 13157484254. Its totient is φ = 13157484252.
The previous prime is 13157484251. The next prime is 13157484269. The reversal of 13157484253 is 35248475131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8518920804 + 4638563449 = 92298^2 + 68107^2 .
It is a cyclic number.
It is not a de Polignac number, because 13157484253 - 21 = 13157484251 is a prime.
Together with 13157484251, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13157484251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6578742126 + 6578742127.
It is an arithmetic number, because the mean of its divisors is an integer number (6578742127).
Almost surely, 213157484253 is an apocalyptic number.
It is an amenable number.
13157484253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13157484253 is an equidigital number, since it uses as much as digits as its factorization.
13157484253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 403200, while the sum is 43.
The spelling of 13157484253 in words is "thirteen billion, one hundred fifty-seven million, four hundred eighty-four thousand, two hundred fifty-three".
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