Base | Representation |
---|---|
bin | 1011111110001101001000… |
… | …1000011011100000101110 |
3 | 1201121101210101002020221020 |
4 | 2333203102020123200232 |
5 | 3211131422114021032 |
6 | 43555050002115010 |
7 | 2526005655151050 |
oct | 277432210334056 |
9 | 51541711066836 |
10 | 13163305220142 |
11 | 42155876a2750 |
12 | 158717834ba66 |
13 | 7463a99143ac |
14 | 3371708b38d0 |
15 | 17c61b3a8b2c |
hex | bf8d221b82e |
13163305220142 has 128 divisors (see below), whose sum is σ = 33382150963200. Its totient is φ = 3360783830400.
The previous prime is 13163305220111. The next prime is 13163305220171. The reversal of 13163305220142 is 24102250336131.
13163305220142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×131633052201423 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 558204792 + ... + 558228372.
It is an arithmetic number, because the mean of its divisors is an integer number (260798054400).
Almost surely, 213163305220142 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13163305220142, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16691075481600).
13163305220142 is an abundant number, since it is smaller than the sum of its proper divisors (20218845743058).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13163305220142 is a wasteful number, since it uses less digits than its factorization.
13163305220142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44142.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 13163305220142 its reverse (24102250336131), we get a palindrome (37265555556273).
The spelling of 13163305220142 in words is "thirteen trillion, one hundred sixty-three billion, three hundred five million, two hundred twenty thousand, one hundred forty-two".
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